9x^2+50x+46=0

Solution for 9x^2+50x+46=0 equation:

9x^2+50x+46=0

a = 9; b = 50; c = +46;
Δ = b2-4ac
Δ = 502-4·9·46
Δ = 844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{844}=\sqrt{4*211}=\sqrt{4}*\sqrt{211}=2\sqrt{211}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{211}}{2*9}=\frac{-50-2\sqrt{211}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{211}}{2*9}=\frac{-50+2\sqrt{211}}{18}
$